Bipartite Graph

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A Bipartite Graph is a graph whose vertices can be divided into two independent sets, U and V such that every edge (u, v) either connects a vertex from U to V or a vertex from V to U. In other words, for every edge (u, v), either u belongs to U and v to V, or u belongs to V and v to U. We can also say that there is no edge that connects vertices of same set.
A bipartite graph is possible if the graph coloring is possible using two colors such that vertices in a set are colored with the same color. Note that it is possible to color a cycle graph with even cycle using two colors. For example, see the following graph.
It is not possible to color a cycle graph with odd cycle using two colors.
Java Implementation:
1. Using BFS:
Algorithm to check if a graph is Bipartite:
One approach is to check whether the graph is 2colorable.
Following is a simple algorithm to find out whether a given graph is Bipartite or not using Breadth First Search (BFS).
 Assign RED color to the source vertex (putting into set U).
 Color all the neighbors with BLUE color (putting into set V).
 Color all neighborâ€™s neighbor with RED color (putting into set U).
 This way, assign color to all vertices such that it satisfies all the constraints of m way coloring problem where m = 2.
 While assigning colors, if we find a neighbor which is colored with same color as current vertex, then the graph cannot be colored with 2 vertices (or graph is not Bipartite)
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2. Using DFS
The graph is given in the following form: graph[i] is a list of indexes j for which the edge between nodes i and j exists. Each node is an integer between 0 and graph.length  1. There are no self edges or parallel edges: graph[i] does not contain i, and it doesnâ€™t contain any element twice.Example 1:
Input: [[1,3], [0,2], [1,3], [0,2]]
Output: true
Explanation:
The graph looks like this:
01     32
We can divide the vertices into two groups: {0, 2} and {1, 3}.
Example 2:
Input: [[1,2,3], [0,2], [0,1,3], [0,2]]
Output: false
Explanation:
The graph looks like this:
01  \   \  32
We cannot find a way to divide the set of nodes into two independent subsets.
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Related Topics:
 Graph Representation
 DFS
 Two End BFS
 Topological Sort
 Finding Cycles
 Cycle Detection Using DFS
 All Paths Between Two Nodes
The above content is written by:
Abhishek Dey
A Visionary Software Engineer With A Mission To Empower Every Person & Every Organization On The Planet To Achieve More
Microsoft  University of Florida
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