Least Frequently Used (LFU) Caching Algorithm
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Related Chapter:
LRU Cache
Problem Statement:
Design and implement a data structure for Least Frequently Used (LFU) cache. It should support the following operations: get and put.get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.
put(key, value) - Set or insert the value if the key is not already present. When the cache reaches its capacity, it should invalidate the least frequently used item before inserting a new item. For the purpose of this problem, when there is a tie (i.e., two or more keys that have the same frequency), the least recently used key would be evicted.
Both get and put must be O(1).
Java and Python Solution:
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